Question

dada a função quadrática f(x) = 3x² — 4x + 1, resolva casa uma abaixo:
a- f(1)
b- f(2)
c- f(3)
d- f(√2)​​

Answer 1

A) f(1)

$\begin{gathered}\boxed{\begin{array}{lr} { \mathtt{f(1) = 3. {1}^{2} - 4(1) + 1 }} \\ \\ f(1) = 3 - 4 + 1 \\ \\ \mathtt{ \red{f(1) = 0}}\end{array}}\end{gathered}$

B) f(2)

$\begin{gathered}\boxed{\begin{array}{lr} { \mathtt{f(2) = 3. {2}^{2} - 4(2) + 1}} \\ \\ f(2) = 3.4 - 8 + 1 \\ \\ f(2) =12 - 7 \\ \\ \mathtt{ \green{f(2) = 5}}\end{array}}\end{gathered}$

C) f(3)

$\begin{gathered}\boxed{\begin{array}{lr} { \mathtt{f(3) = 3. {3}^{2} - 4(3) + 1 }} \\ \\ f(3) = 3.9 - 12 + 1\\ \\ f(3) = 27 - 11 \\ \\ \mathtt{ \purple{f(3) = 16}}\end{array}}\end{gathered}$

D) f(✓2)

$\begin{gathered}\boxed{\begin{array}{lr} { \mathtt{f( \sqrt{2) } = 3.( { \sqrt{2} )}^{2} - 4 \sqrt{2} + 1 }} \\ \\ f( \sqrt{2} ) = 3.2 - 4 \sqrt{2} + 1 \\ \\f( \sqrt{2} ) = 6 + 1 - 4 \sqrt{2} \\ \\ \mathtt{ \orange{f( \sqrt{2}) = 7 - 4 \sqrt{2} }}\end{array}}\end{gathered}$

Espero ter ajudado!