Question

dada a funçao quadratica f(x) =-3×^2+6×+9 caucule f(4)

Answer 1

f(x) = -3x²+6x+9
f(4)=-3.4²+6.4+9
f(4)=-3.16+24+9
f(4)=-48+23
f(4)=-25

Answer 2

f(x) = - 3x² + 6x + 9
f(4) = - 3(4)² + 6.4 + 9
f(4) = - 48 + 24 + 9 = - 15