Dada a função quadrática f(x)= 2x - 2x + 4 determine:
a) f ( -1 ) =
b) f ( 2 ) =
c) f ( 2/3 ) =
Soluções para a tarefa
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a f=-1
b f=-2
c f=-2 e -3
b f=-2
c f=-2 e -3
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f(x) = 2x - 2x + 4
a) f(-1)
f(-1) = 2(-1) - 2(-1) + 4
f(-1) = -2 - (-2) + 4
f(-1) = 2 + 2 + 4
f(-1) = 0 + 4
f(-1) = 4
b) f( 2 )
f(2) = 2 (2) - 2(2) + 4
f(2) = 4 - 4 + 4
f(2) = 0 + 4
f(2) = 4
c) f(2/3)
f(2/3) = 2(2/3) - 2 (2/3) + 4
f(2/3) = 4/3 - 4/3 + 4
f(2/3) = 0 + 4
f (2/3) = 4
a) f(-1)
f(-1) = 2(-1) - 2(-1) + 4
f(-1) = -2 - (-2) + 4
f(-1) = 2 + 2 + 4
f(-1) = 0 + 4
f(-1) = 4
b) f( 2 )
f(2) = 2 (2) - 2(2) + 4
f(2) = 4 - 4 + 4
f(2) = 0 + 4
f(2) = 4
c) f(2/3)
f(2/3) = 2(2/3) - 2 (2/3) + 4
f(2/3) = 4/3 - 4/3 + 4
f(2/3) = 0 + 4
f (2/3) = 4
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