Question

Dada a função quadrática determine.... com cálculos pfv

Answer 1

a) f(1) = 3(1)² - 4(1) + 1
    f(1) = 3 - 4 + 1
    f(1) = 0

b) f(2) = 3(2)² - 4(2) + 1
    f(2) = 3.4 - 8 +1
    f(2) = 5

c) f(0) = 3(0)² - 4(0) + 1
    f(0) = 0 - 0 + 1
    f(0) = 1

d) f(√2) = 3(√2)² - 4(√2) + 1
    f(√2) = 3√2 - 4√2 + 1
    f(√2) = 2√2

e) f(-2) = 3(-2)² - 4(-2) + 1
    f(-2) = 3.4 + 8 +1
    f(-2) = 21