Question

Dada a função polinomial do 2 grau y=3x2-5x+2,determine:

A)os coeficientes a,b e c da função.

B)os valores de y para x=1 e x=2/3

Answer 1

f(x)=3x²-5x+2

a)
f(x)=ax²+bx+c

a=3
b=-5
c=2

b)

x=1
f(1)=3*1²-5*1+2
f(1)=3*1-5+2
f(1)=3-5+2
f(1)=0

x=2/3

f(2/3)= 3(2/3)²-5(2/3)+2
f(2/3)=3(4/9)-10/3+2
f(2/3)=12/9-10/3+2
f(2/3)=-18/9+2
f(2/3)=-2+2
f(2/3)=0

Answer 2

Resposta:

f(x)=3x²-5x+2

a)

f(x)=ax²+bx+c

a=3

b=-5

c=2

b)

x=1

f(1)=3*1²-5*1+2

f(1)=3*1-5+2

f(1)=3-5+2

f(1)=0

x=2/3

f(2/3)= 3(2/3)²-5(2/3)+2

f(2/3)=3(4/9)-10/3+2

f(2/3)=12/9-10/3+2

f(2/3)=-18/9+2

f(2/3)=-2+2

f(2/3)=0

resposta b

Explicação passo-a-passo: