Question

Dada a função g(x) = 2x2 – 6x – 4, calcule g(1/2) – g(1).

Answer 1

$Dada\ a\ fun\c{c}\tilde{a}o \ g(x) = 2x^2-6x-4, \ calcule\ g(\frac{1}{2}) - g(1).\\ \\g(\frac{1}{2}) = 2\cdot(\frac{1}{2})^2-6\cdot\frac{1}{2}-4= 2\cdot\frac{1}{4}-\frac{6}{2}-4=\frac{2}{4}-3-4=\frac{1}{2}-7\\ \\=\frac{1}{2}-\frac{14}{2}=\frac{1-14}{2}=-\frac{13}{2}\\ \\g(1)=2\cdot1^2-6\cdot1-4= 2\cdot1-6-4= 2-6-4=-8\\ \\ \\ \\ g(\frac{1}{2}) - g(1)=-\frac{13}{2}-(-8)=-\frac{13}{2}+\frac{16}{2}=\frac{-13+16}{2}=\frac{3}{2}$

Answer 2

Boa tarde Brubs

g(x) = 2x² - 6x - 4

g(1/2) = 2/4 - 6/2 - 4 
g(1/2) = 1/2 - 6/2 - 8/2 = -13/2 

g(1) = 2 - 6 - 4 = -8 

g(1/2) - g(1) = -13/2 + 16/2 = 3/2