Question

Dada a função f(x)=x2-x-72, calcule suas raízes

Answer 1

Resposta:

f(x)=x²-x-72

x²-x-72=0

x'=[1+√(1+288)]/2 =(1+17)/2 =9

x''=[1-√(1+288)]/2 =(1-17)/2 =-8