Question

Dada a função f(x)= ) x² - x -6 = 0 quais as suas raízes reais.

Answer 1

Oie, Td Bom?!

$f(x) = x {}^{2} - x - 6$

$0 = x {}^{2} - x - 6$

$x {}^{2} - x - 6 = 0$

$x {}^{2} + 2x - 3x - 6 = 0$

$x \: . \: (x + 2) - 3(x + 2) = 0$

$(x + 2) \: . \: (x - 3) = 0$

$x + 2 = 0 \\ x - 3 = 0$

$x = - 2 \\ x = 3$

S = $\left \{ x_{1} = - 2 \: , \: x_{2} = 3\right \}$

Att. Makaveli1996