Question

Dada a função f(x)=x²-3x+7 ,calcule a f(3),f(0) e f(-3).
Cálculos por favor

Answer 1

f(x) = x² - 3x + 7
f(3) = 3² - 3(3) + 7
f(3) = 9 - 9 + 7
f(3) = 0 + 7
f(3) = 7

f(x) = x² - 3x + 7
f(0) = 0² - 3(0) + 7
f(0) = 0 - 0 + 7
f(0) = 7

f(x) = x² - 3x + 7
f(-3) = (-3)² -3(-3) + 7
f(-3) = 9 + 9 + 7
f(-3) = 18 + 7
f(-3) = 25

Answer 2

f(x) = x² - 3x + 7

a)
x = 3
f(3) = 3² - 3.3 + 7
f(3) = 9 - 9 + 7
f(3) = 0 + 7
f(3) = 7
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b)

x = 0
f(0) = 0² - 3.0 + 7
f(0) = 7
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c)

x = - 3
f(-3) = (-3)² - 3.(-3) + 7
f(-3) = 9 + 9 + 7
f(-3) = 18 + 7
f(-3) = 25