Question

dada a função f(x)=x2-2x-3 determine
f (2)
f(-3)
f(3)
f(4)
​

Answer 1

a) f(x) = x² - 2x - 3

f(2) = 2² - 2×2 - 3

f(2) = 4 - 4 - 3

f(2) = -3

b) f(x) = x² - 2x - 3

f(-3) = (-3)² - 2 × (-3) - 3

f(-3) = (-3)² + 2 × 3 - 3

f(-3) = -3(-3 - 2 + 1)

f(-3) = -3 × (-4)

f(-3) = 12

c) f(x) = x² - 2x - 3

f(3) = 3² - 2 × 3 - 3

f(3) = 9 - 6 - 3

f(3) = 0

d) f(x) = x² - 2x - 3

f(4) = 4² - 2 × 4 - 3

f(4) = 16 - 8 - 3

f(4) = 5