Question

Dada a função f (x)=x2 +2x-3, caucule f(0)

Answer 1

 

Resposta:

f(0) = 0² - 2(0) + 3

f(0) = 0 - 0 + 3

f(0) = 3

Answer 2

Resposta:

F(X) = X² + 2X - 3

F(0) = 0 + 0 - 3

F(0) = -3