Question

Dada a função F(x)=x²-1, calcule o valor para: A= F(1/2) , B= f(1√2) C= f(0) D=( -1)

Answer 1

Olá!

$a) \: \: f(\frac{1}{2} ) =? \\ \\ f(\frac{1}{2} ) = (\frac{1}{2})^2 - 1 \\ f(\frac{1}{2} ) = \frac{1}{4} -1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (1) \: \: \: (4) \\ f(\frac{1}{2} ) = \frac{1-4}{4} \\ f(\frac{1}{2} ) = -\frac{3}{4}$

$b) \: \: f(\sqrt{2} ) = ? \\ \\ f(\sqrt{2} ) = ( \sqrt{2} )^2 -1 \\ f(\sqrt{2} ) = 2 - 1 \\ f(\sqrt{2} ) = 1$

$c) \: \: f(0) = ? \\ \\ f(0) = 0^2 - 1 \\ f(0) = -1$

$d) \: \: f(-1) = ? \\ \\ f(-1) =(-1)^2 - 1 \\ f(-1) = 1-1 \\ f(-1) = 0$

Boa interpretação!!

Answer 2

Vamos lá

Calculando os valores da função:

f ( X ) = X² - 1
________________

A ) f ( 1 / 2 ) = 1 / 2² - 1

f ( 1 / 2 ) = 1 / 4 - 1

f ( 1 / 2 ) = - 3 / 4

S ( - 3 / 4 )
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B ) f ( 1√2 ) = 1√2² - 1

f ( 1√2 ) = 2 - 1

f ( 1√2 ) = 1

S ( 1 )
_________________

C ) f ( 0 ) = 0² - 1

f ( 0 ) = 0 - 1

f ( 0 ) = - 1

S ( - 1 )
__________________

D ) f ( - 1 ) =( -1 ) ² - 1

f ( - 1 ) = 1 - 1

f ( - 1 ) = 0

S ( 0 )