Question

Dada a função f x = x ao quadrado- 5 x +6 calcule

Answer 1

Resposta:

f(x) = x² - 5x + 6

a = 1

b = -5

c = 6

delta

d = 25 - 24 = 1

x1 = (5 + 1)/2 = 3

x2 = (5 - 1)/2 = 2

o vértice

Vx = -b/2a = 5/2

Vy = -d/4a = -1/4

Answer 2

Resposta:

$x=3,\:x=2$

Explicação passo a passo:

$f\left(x\right)=x\:^2-5x+6$

$x^2-5x+6=0$

$x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:1\cdot \:6}}{2\cdot \:1}$

$x_{1,\:2}=\frac{-\left(-5\right)\pm \:1}{2\cdot \:1}$

$x_1=\frac{-\left(-5\right)+1}{2\cdot \:1},\:x_2=\frac{-\left(-5\right)-1}{2\cdot \:1}$

$x_1=\frac{-\left(-5\right)+1}{2\cdot \:1}=\frac{5+1}{2\cdot \:1}=\frac{6}{2\cdot \:1}=\frac{6}{2}=3$

$x_2=\frac{-\left(-5\right)-1}{2\cdot \:1}=\frac{5-1}{2\cdot \:1}=\frac{4}{2\cdot \:1}=\frac{4}{2}=2$

$x=3,\:x=2$