Question

Dada a funcao f(x)= x+2 sobre x ao quadrado menos 4. Calcule f(0) f(1) f(3) e f(4).

Answer 1

Boa tarde

f(x) = (x + 2)/(x² - 4) 

f(0) = (0 + 2)/(0² - 4) = -2/4 = -1/2 

f(1) = (1 + 2)/(1² - 4) = -3/3 = -1 

f(3) = (3 + 2)/(3² - 4) = 5/5 = 1

f(4) = (4 + 2)/(4² - 4) = 6/12 = 1/2 

Answer 2

f(x)=x+2/x²-4
f(0)=0+2/0²-4→ f(0)=0

f(1)=1+2/1²-4= 3/1-4=3/-3=-1→f(1)=-1

f(3)=3+2/3²-4= 5/9-4= 5/5= 1→f(3)=1

f(4)= 4+2/4²-4= 6/12= 1/2= 0,5→ f(4)= 0,5

Att= Professor Lucas Silva!