Question

Dada a função f(x) = 3ˣ , calcule:
a) f (3) · f (0) · f (1/2) · f (-2)



b) f (3) · f (1/2) ÷ f (-2)

Answer 1

Dada a função f(x) = 3ˣ , calcule:

a) f (3) · f (0) · f (1/2) · f (-2)

F(x)=3^x

F(3)=3^3=3.3.3=9.3=27

F(0)=3^0=1

F(1/2)=3^1/2=√3

F(-2)=3^(-2)=1/9

f (3) · f (0) · f (1/2) · f (-2)=

=27.(1).(√3).(1/9)

=27.√3.(1/9)

=3√3

b) f (3) · f (1/2) ÷ f (-2)

F(x)=3^x

F(3)=3^3=3.3.3=9.3=27

F(1/2)=3^1/2=√3

F(-2)=3^-2=1/9

b)

f (3) · f (1/2) ÷ f (-2)=27.√3÷(1/9)

F(3).f(1/2)÷f(-2)=

=27.√3÷(3^-2)

=3^3.3^(1/2).3^-2

=3^11/2

=√3^11

=√3^10.3

=√59049×3

=√59049×√3

=243√3

Answer 2

Vamos aos cálculos.

a)

3³ . 3° . 3½ . 3-² ( Somamos os expoentes)
3³ . 3-³/²
3³/²
√3.3²
3√3 resposta

b)

3³ . 3½
_____
3-²

3^(7/2). 3²

3¹¹/² =

√(3².3².3².3².3².3)
3.3.3.3.3√3
243√3 resposta