Question

Dada a função f(x)=2x²-6x-4 g(x) -3x²-5x+1 calcule :
F(3)
F(-2)
F(0)
F(-0,2)
G(1)
G(-4)
G(0)
G(1
2)

Answer 1

f(x) = 2x² - 6x - 4

f(3) = 2(3)² - 6(3) - 4 = 18 - 18 - 4 ∴ f(3) = -4

f(-2) = 2(-2)² - 6(-2) - 4 = 8 + 12 - 4 ∴ f(-2) = 16

f(0) = 2(0)² - 6(0) - 4 = 0 - 0 - 4 ∴ f(0) = -4

f(-0,2) = 2(-0,2)² - 6(-0,2) - 4 = 0,08 + 0,12 - 4 ∴ f(-0,2) = -3,8

g(x) = -3x² - 5x + 1

g(1) = -3(1)² - 5(1) + 1 = -3 - 5 + 1  ∴ g(1) = -7

g(-4) = -3(-4)² - 5(-4) + 1 = 48 + 20 + 1 ∴ g(-4) = 69

g(0) = -3(0)² - 5(0) + 1 = 0 - 0 + 1 ∴ g(0) = 1

g(12) = -3(12)² - 5(12) + 1 = -432 - 60 + 1 ∴ g(12) = -491