Question

Dada a Função f(x)=2x²-4x+1,Calcule
f(0):
f(1/2)
f(√3)

Answer 1

$f(x)=2x^2-4x+1\\ \\ f(0)=2*0^-4*0+1=0+0+1=1\\ \\ f(\frac{1}{2})=2.(\frac{1}{2})^2-4.(\frac{1}{2})+1=\frac{1}{2}-2+1=-\frac{1}{2}\\ \\ f(\sqrt3)=2.(\sqrt3)^2-4\sqrt3+1=6-4\sqrt3+1=5+4\sqrt3$