Question

Dada a função f definida por f(x) = 2x + 1, determine f–¹(3):

Answer 1

y=2x+1
2x=y-1
x=$\frac{y-1}{2}$
logo, f$x^{-1}$(x) = $\frac{x-1}{2}$

f$x^{-1}$(3) = $\frac{3-1}{2}$
f$x^{-1}$(3) = 1

Answer 2

Boa noite

y = 2x + 1

2x = y - 1
x = (y - 1)/2

f^(-1)(x) = (x - 1)/2
f^(-1)(3) = (3 - 1)/2 = 2/2 = 1