Question

dada a função do 2º grau f (x) =2x elevado 2 - 1, calcule:
f (2)
f (-1)
f (0)
f (1sobre2)
f (√2)

Answer 1

$a) f(2) = 2.( 2^{2} )-1 = 2.4 - 1 = 7 \\ \\ b) f(-1) = 2.( -1)^{2} -1 = 2.1 -1 = 1 \\ \\ c) f(0) = 2. 0^{2} -1 = 0-1 = -1 \\ \\ f( \frac{1}{2} ) = 2. (\frac{1}{2})^{2} -1 = 2. \frac{1}{4} -1 = \frac{2}{4} -1 = \frac{2-4}{4} = - \frac{2}{4} = - \frac{1}{2}$

e)
$f( \sqrt{2} ) = 2. (\sqrt{2})^{2} -1 = 2.2-1 = 4-1 = 3$