Question

dada a função definida por f (x)=x²+2x+1, calcular f (-3), f (0), f (1), f (2)

Answer 1

F(-3)= (-3)² + 2(-3) +1  = 9 - 6 +1 = 3 +1 = 4

f(0)= 0² +2.0 +1 = 0 + 0 +1 = 1

f(1) = 1² +2.1 +1 = 1 +2 + 1= 4

f(2) = 2² +2.2 +1 = 4 + 4 +1 = 9

Answer 2

f(-3) = (-3)² + 2 * 3 + 1 => f(-3) = 9 + 6 +1 => "f(-3) = 16"

f(0) = 0² + 2 * 0 + 1 => f(0) = 0 + 0 + 1 => "f(0) = 1"

f(1) = 1² + 2 * 1 + 1 => f(1) = 1 + 2 + 1 => "f(1) = 4"

f(2) = 2² + 2 * 1 + 1 => f(2) = 4 + 2 + 1 => "f(2) = 7"