Question

dada a função definida por f(x)=3x +1 caucule f(5)-f(2)
f(0)

Answer 1

f(5) - f(2):
f(x) = 3x + 1 >> f(5) = 3×5 + 1 >> f(5) = 15 + 1 >> f(5) = 16
f(x) = 3x + 1 >> f(2) = 3×2 + 1 >> f(2) = 6 + 1 >> f(2) = 7

f(5) - f(2) = 16 - 7 = 9


f(0):
f(x) = 3x + 1 >> f(0) = 3×0 + 1 >> f(0) = 0 + 1 >> f(0) = 1

Answer 2

Resposta:

f(5) - f(2):

f(x) = 3x + 1 >> f(5) = 3×5 + 1 >> f(5) = 15 + 1 >> f(5) = 16

f(x) = 3x + 1 >> f(2) = 3×2 + 1 >> f(2) = 6 + 1 >> f(2) = 7

f(5) - f(2) = 16 - 7 = 9

f(0):

f(x) = 3x + 1 >> f(0) = 3×0 + 1 >> f(0) = 0 + 1 >> f(0) = 1

$_$