Question

Dada a equação -x² - x + 6 = 0, podemos afirmar que o conjunto de soluções dessa equação é:

Answer 1

$\Box \ \ \boxed{\begin{array}{l}\sf -x^2-x+6= \end{array}}\\\\\\\Box \ \ \boxed{\begin{array}{l}\sf a=-1 \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf b=-1 \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf c=6 \end{array}}$

$\Box \ \ \boxed{\begin{array}{l}\sf \Delta=(-1)^2-4.-1.6 \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf \Delta=1+24 \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf \Delta=5 \end{array}}$

$\Box \ \ \boxed{\begin{array}{l}\sf x=\frac{-b\pm\sqrt{\Delta}}{2.a} \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf x=\frac{1\pm5}{2.-1} \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf x=\frac{1\pm5}{-2} \end{array}}$

$\Box \ \ \boxed{\begin{array}{l}\sf x'=\frac{1+5}{-2} \end{array}}\boxed{\begin{array}{l}\sf x'=\frac{6}{-2} \end{array}}\boxed{\begin{array}{l}\sf x'=-3 \end{array}}\\\\\\\Box \ \ \boxed{\begin{array}{l}\sf x''=\frac{1-5}{-2} \end{array}}\boxed{\begin{array}{l}\sf x''=\frac{-4}{-2} \end{array}}\boxed{\begin{array}{l}\sf x''=2 \end{array}}$

Resposta correta;

$S=\{2 \ , -3 \}$

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