Question

dada a dizima periódica 0,12525...qual e a fração geratriz

Answer 1

$x=0,12525...=0,1\overline{25}\\ \\ 100x=12,52525...\\ \\ \\ 100x-x=12,52525...-0,12525...\\ \\ 99x=12,5\overline{25}-0,1\overline{25}\\ \\ 99x=12,5-0,1\\ \\ 99x=12,4\\ \\ 990x=124\\ \\ x=\dfrac{124}{990}\\ \\ \boxed{x=\dfrac{62}{495}}$