Question

dada a distancia entre o ponto A eB igual a 10 e o ponto A(-2,5) B(x,x-7) . Determine o ponto B

Answer 1

dAB=√(x+2)²+(x-7-5)²=10
√x²+4x+4+x²-24x+144=10
(√2x²-20x+148)²=10²
2x²-20x+148=100
2x²-20x+48=0
∆=(-20)²-4.2.48
∆=400-384
∆=16
x=-(-20)±√16/2.2
x'=20+4/4=6
x''=20-4/4=4