Question

d) ×^2-5×+3)+(4×^2-2×)

e) ×^2+6×+16)-(×^2+2×+16)

f) (×^3+3×^2+4×)+ (10×^2+5×)

Answer 1

d)
$(x^2-5x+3)+(4x^2-2x)=\\x^2-5x+3+4x^2-2x=\\x^2+4x^2-5x-2x+3=\\5x^2-7x+3$

e)
$(x^2+6x+16)-(x^2+2x+16)=\\x^2+6x+16-x^2-2x-16=\\x^2-x^2+6x-2x+16-16=\\0+4x+0=\\4x$

f)
$(x^3+3x^2+4x)+(10x^2+5x)=\\x^3+3x^2+4x+10x^2+5x=\\x^3+3x^2+10x^2+4x+5x=\\x^3+13x^2+9x$