Question

Cos510+sen300-tg585-cos90

Answer 1

cos510°=720-510=210=360-210=150=-cos30°
sen300°=360-300=60=-sen60°
-tg585=720-585=135=180-135=-(-tg45)=tg45°
cos90=0


-cos30+(-sen60)-(tg45)-cos90
-raiz3/2-raiz3/2-1-0=-2.(rais3/2)-1=-raiz3-1=+1,7-1=2,7