Question

Coordenadas do vértice da parábola que representava função y=4x²-2x+6

Answer 1

Resposta:

$\text{V}\left(\dfrac{1}{4},\dfrac{23}{4}\right)$

Explicação passo-a-passo:

$y=4x^2-2x+6$

$\Delta=(-2)^2-4\cdot4\cdot6=4-96=-92$

$x_{\text{V}}=\dfrac{-b}{2a}=\dfrac{-(-2)}{2\cdot4}=\dfrac{2}{8}=\dfrac{1}{4}$

$y_{\text{V}}=\dfrac{-\Delta}{4a}=\dfrac{-(-92)}{4\cdot4}=\dfrac{92}{16}=\dfrac{23}{4}$