Question

CONTEÚDO TEOREMA DE PITÁGORAS.
Calcule o Alfa e o Beta das questões A e B.​

Answer 1

a)

${x}^{2} = {8}^{2} + {6}^{2} \\ {x}^{2} = 64 + 36 \\ {x}^{2} = 100 \\ x = \sqrt{100} \\ x = 10$

$\cos( \alpha ) = \frac{8}{10} = \frac{4}{5} \\ \alpha = arc \cos( \frac{4}{5} ) \\ \alpha = 36,86$

$\beta = 90 - 36,86 \\ \beta = 53,14$

b)

$\tan( \beta ) = \frac{1}{2} \\ \beta = arc \tan( \frac{1}{2} ) \\ \beta = 26,56$

$\alpha = 90 - 26,56 = 63,44$