Question

conta de log 5/12 (fração) com base 6

Answer 1

$log_6 \frac{5}{12} = log_65 - log_612 = \frac{log5}{log6} - \frac{log12}{log6} = \frac{log5-log12}{log6} \\ \\ \frac{log \frac{10}{2} - log4*3}{log3*2} = \frac{log10-log2-log4+log3}{log3+log2} = \frac{1-log2-log2+log2+log3}{log3+log2}$

Adotemos $log2 = 0,30$ e $log3 = 0,47$

$\frac{1-log2-log2+log2+log3}{log3+log2} = \frac{1-0,30-0,30+0,30+0,47}{0,47+0,30} = \frac{1,17}{0,77} = 1,5$