Question

construa a matriz(Aij) 3x3 sendo aij = 2j + 4i​

Answer 1

$\mathsf{A}=\begin{vmatrix}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\a_{31}&a_{32}&a_{33}\end{vmatrix}$

$\mathsf{a_{11}=4.1+2.1=4+2=6}\\\mathsf{a_{12}=4.1+2.2=4+4=8}\\\mathsf{a_{13}=4.1+2.3=4+6=10}$

$\mathsf{a_{21}=4.2+2.1=8+2=10}\\\mathsf{a_{22}=4.2+2.2=8+4=12}\\\mathsf{a_{23}=4.2+2.3=8+6=14}$

$\mathsf{a_{31}=4.3+2.1=12+2=14}\\\mathsf{a_{32}=4.3+2.2=12+4=16}\\\mathsf{a_{33}=4.3+2.3=12+6=18}$

$\mathsf{A}=\begin{vmatrix}6&8&10\\10&12&14\\14&16&18\end{vmatrix}$