Considere o seguinte sistema linear e assinale a alternativa que corresponde à sua solução.
open curly brackets table attributes columnalign left end attributes row x cell negative 2 y end cell cell plus z end cell equals 3 row cell negative 2 x end cell cell plus y end cell cell plus z end cell equals cell negative 1 end cell row cell negative x end cell blank cell plus 2 z end cell equals 0 row blank end table close
a.
x equals 2 over 3, y equals 0 e z equals 2 over 3.
b.
x equals negative 1 third, y equals negative 1 third e z equals negative 1 third.
c.
x equals negative 2 over 3, y equals negative 1 e z equals negative 1 third.
d.
x equals 1, y equals negative 2 over 3 e z equals negative 1 third.
e.
x equals negative 2 over 3, y equals negative 2 e z equals negative 1 third.
Soluções para a tarefa
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Resposta:
x equals negative 2 over 3, y equals negative 2 e z equals negative 1 third.
Explicação passo a passo:
x=-2/3 y-2 z = -1/3
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