Matemática, perguntado por krlossantos, 3 meses atrás

Considere o seguinte sistema linear e assinale a alternativa que corresponde à sua solução.

open curly brackets table attributes columnalign left end attributes row x cell negative 2 y end cell cell plus z end cell equals 3 row cell negative 2 x end cell cell plus y end cell cell plus z end cell equals cell negative 1 end cell row cell negative x end cell blank cell plus 2 z end cell equals 0 row blank end table close
a.

x equals 2 over 3, y equals 0 e z equals 2 over 3.
b.

x equals negative 1 third, y equals negative 1 third e z equals negative 1 third.
c.

x equals negative 2 over 3, y equals negative 1 e z equals negative 1 third.
d.

x equals 1, y equals negative 2 over 3 e z equals negative 1 third.
e.

x equals negative 2 over 3, y equals negative 2 e z equals negative 1 third.

Soluções para a tarefa

Respondido por milenaguarda963
21

Resposta:

x equals negative 2 over 3, y equals negative 2 e z equals negative 1 third.

Explicação passo a passo:

x=-2/3 y-2 z = -1/3

Perguntas interessantes