Question

Considere log 2 = 0,30 e log 3 = 0,48, calcule:

A) log √6

Answer 1

Seguem as propriedades: 
log √6 = log 6¹/² = 1/2 * log 6

Log 6 = log (3*2) = log 3 + log 2

logo,
1/2*log 6 = 1/2*(log 3+log 2) = 1/2*(0,48+0,30) = 1/2*0,78 = 0,39 

Resposta:
log√6 = 0,39

Answer 2

log \/6 = log 6^1/2 = log (3x2)^1/2 = 1/2.(log 3 + log 2) = 1/2 . (0,30 + 0,48)
= 1/2 . (0,78) = 0,78/2 = 0,39