Question

Considere as medidas abaixo e calcule o cateto que falta hipotenusa mede 19 cm e cateto mede 60 mm

Answer 1

$\boxed{h^2 = c^2 + c^2}$


Transformando mm em cm..

1 cm----10 mm
x cm-----60 mm

10x = 60

x = 60/10

x = 6 cm
________________________________________________
$19^2 = 6^2 + c^2\\\\361=36+c^2\\\\c^2=361-36\\\\c^2=325\\\\c= \sqrt{325} \\\\c \approx 18,02$



Forte abraço!

Answer 2

a = 19 cm 
1 cm  = 10 mm
19 cm * 10  = 190 mm ***  ( a)
b = 60 mm
a² = b² + c² 
190²  = 60² + c² 
36100 = 3600 + c²
36100 - 3600 = c²
c² = 32500
Vc² = V32500
c = V(2² .5² .5².13 ) = 2 * 5 * 5 * V13 = 50V13 ****