Question

Considere agora BC//DE. Aplique o teorema de Tales no triângulo e calcule o valor de x.​

Answer 1

$\large\boxed{\begin{array}{l} \rm \dfrac{4}{2} = \dfrac{x + 8}{x - 2} \\ \\ \rm \: 4(x - 2) = 2(x + 8) \\ \\ \rm \: 4x - 8 = 2x + 16 \\ \\ \rm \: 4x - 2x = 16 + 8 \\ \\ \rm \: 2x = 24 \\ \\ \rm \: x = \dfrac{24}{2} \\ \\ \boxed{\rm x = 12} \leftarrow \sf{Letra \: B}\end{array}}$