Question

Considere a pg de termos não nulos (2ax,4ax elevado a 2) Qual é o 10 termo dessa pg?

Answer 1

$\Large\boxed{\begin{array}{l}\sf(2ax,4ax^2\dotsc)\\\sf q=\dfrac{4ax^2}{2ax}=2x\\\sf a_{10}=a_2\cdot q^8\\\sf a_{10}=4ax^2\cdot(2x)^{8}\\\sf a_{10}=4ax^2\cdot256x^8\\\\\Huge\boxed{\boxed{\boxed{\boxed{\sf a_{10}=1024ax^{10}}}}}\end{array}}\checkmark$