Question

Considere a função f: R -> R, em que
$f(x) = {2}^{x}$
O valor de f(a+1) - f(a) é?​

Answer 1

$f(x) = {2}^{x} \\ f(a + 1) = {2}^{a + 1 } \\ f(a) = {2}^{a}$

$f(a + 1) - f(a) = {2}^{a + 1} - {2}^{a} \\ f(a + 1) - f(a) = {2}^{a}.2 - {2}^{a} \\ f(a + 1) - f(a) = {2}^{a}(2 - 1) \\ = {2}^{a} = f(a)$