Question

Considere
a função f, de domínio N, definida por f(1) = 4 e f(x+1) = 3.f(x) – 2. Calcule
o valor






   de f(0)

Answer 1

$f(x+1)=3\cdot\,f(x)-2\\\\f(0+1)=3\cdot\,f(0)-2\\\\f(1)=3\cdot\,f(0)-2\\\\4=3\cdot\,f(0)-2\\\\4+2=3\cdot\,f(0)\\\\3\cdot\,f(0)=6\\\\f(0)=\frac{6}{3}\\\\\boxed{f(0)=2}$