Question

Considerando que log 2 = 0,3 e log 3 = 0,47 calcule: a) log 6 b) log 24 c) log 48 d) log 60

Answer 1

a) $log 6 = log (2*3) \\ log2 + log3\\ 0,3+0,47 = 0,77$

b)$log24=log(2*2*2*3)\\ log2+log2+log2+log3\\0,3+0,3+0,3+0,47\\1,37$

c)$log48=log(24*2)\\ log24+log2\\1,37+0,3= 1,67$

d)$log60=log(2*2*3*5)\\log2+log2+log3+log(10/2)$
$0,3+0,3+0,47+(log10-log2)\\ 1,04+1-0,3\\ 1,74$