Question

considerando log²10=o,3010 e log³10 =0,4771 então log de 0,6 é igual a :

Answer 1

$log0,6=log\frac{6}{10}=log6-log10=log(2.3)-log10=log2+log3-log10\\ \\ =0,3010+0,4771-1=-0,2219$

Answer 2

$\circ \ \text{log} \ 2 = 0,3010 \\ \circ \text{log} \ 3 = 0,4771 \\\\ \bullet \text{log} \ (\frac{3 \cdot 2}{10}) = x \\\\ \text{log} \ (3 \cdot 2) - \text{log} \ 10 = x \\\\ (\text{log} \ 3 + \text{log} \ 2) - \text{log} \ 10 = x \\\\ (0,3010 + 0,4771) - 1 = x \\\\ 0,7781 - 1 = x \\\\ \boxed{x = - 0,2219}$