Question

como simplificar as frações abaixo  usando mdc do numerador  e do denominadora)24/32       b)20/35       c) 14/28        d)7/21            e)40/60

Answer 1

mdc  24,32 = 8
24 = 2³ * 3 
32 = 2^5

mdc 20,35  = 5
20 = 2² * 5
35 = 5 * 7

mdc 14,28 = 14
14 = 2 * 7
28 = 2² * 7

mdc 7,21 =  7
7 = 7
21 = 3 * 7

mdc 40,60 = 20
40 = 2³ * 5
60 =2² * 3 * 5

MDC = TERMOS COMUNS COM MENOR EXPOENTE
24/32 = ( 24:8)/(32:8) = 3/4 ***
20/35 = (20:5)/(35:5) = 4/7 ***
14/28 = ( 14:14)/(28:14) =1/2 ***
7/21 = ( 7:7)/ ( 21:7)  = 1/3 ***
40/60 = ( 40:20)/(60:20) = 2/3****

Answer 2

a) $\frac{24^{\div2}}{32^{\div2}} = \frac{12^{\div2}}{16^{\div2}} = \frac{6^{\div2}}{8^{\div2}} = \boxed{\begin{array}{c}\mathsf{\frac{3}{4}} \end{array}}$


b) $\frac{20^{\div5}}{35^{\div5}} = \boxed{\begin{array}{c}\mathsf{\frac{4}{7}} \end{array}}$


c) $\frac{14^{\div2}}{28^{\div2}} = \frac{7^{\div7}}{14^{\div7}} =\boxed{\begin{array}{c}\mathsf{\frac{1}{2}} \end{array}}$


d) $\frac{7^{\div7}}{21^{\div7}} = \boxed{\begin{array}{c}\mathsf{\frac{1}{3}} \end{array}}$


e) $\frac{40^{\div2}}{60^{\div2}} = \frac{20^{\div2}}{30^{\div2}} = \frac{10^{\div5}}{15^{\div5}} = \boxed{\begin{array}{c}\mathsf{\frac{2}{3}} \end{array}}$

Espero ter ajudado, qualquer dúvida comente embaixo! :)