Question

como se resolve?
(t-1)^4

Answer 1

$(t-1)^4=\binom{4}{0}t^4(-1)^0+\binom{4}{1}t^3(-1)^1+\binom{4}{2}t^2(-1)^2+\binom{4}{3}t^1(-1)^3+\binom{4}{4}t^0(-1)^4$

$\boxed{t^4-4t^3+6t^2-4t+1}$