Question

como se resolve essa equação do segundo grau 4x²-12x+10=0

Answer 1

$\mathtt{4x\²-12x+10=0} \\ \\ \mathtt{a = 4} \\ \mathtt{b = -12} \\ \mathtt{c = 10} \\ \\ \mathtt{\Delta = b^2 -4 \times a \times c} \\ \mathtt{\Delta = (-12)^2 -4 \times 4 \times 10} \\ \mathtt{\Delta = 144 - 16 \times 10} \\ \mathtt{\Delta =144 - 160 } \\ \mathtt{\Delta = -16} \\ \\ \\ \boxed{\mathtt{Por ~\Delta ~ser ~menor~que ~0, ~n\~ao~existe~raiz~exata}}$