Question

Como se interpolar 6 meios aritméticos entre 2 e 10 nessa ordem?

Answer 1

2 _  _  _  _  _  _ 10

an = a₁ + (n-1)r
10 = 2 + (8-1)r
10 = 2 + 7r
10-2 = 7r
8=7r
r = 8/7

a₂ = a₁ + r 
a₂ = 2 + 2/7
a₂ = 16/7

a₃ = 2 + 2. 8/7
a₃ = 2 + 16/7
a₃ = 30/7

a₄ = 2 + 3.8/7
a₄ = 2 + 24/7
a₄ = 38/7

a₅ = 2 + 4.8/7
a₅= 2 + 32/7
a₅ = 46/7

a₆ = 2 + 5.8/7
a₆ = 2 + 40/7
a₆ = 54/7

a₇ = 2 + 6.8/7
a₇ = 2 + 48/7
a₇ = 62/7

PA ( 2 , 16/7, 30/7, 38/7, 46/7, 54/7, 62/7, 10)