Question

como resolvo esse logaritimo?log0,25 na base 4?

Answer 1

$log_{4}(0.25) = \times \\ {4}^{x} = 0.25 \\ ( { {2}^{2}) }^{x} = \frac{1}{4} \\ ( { {2}^{2}) }^{x} = {2}^{ - 2} \\ 2x = - 2 \\ \times = - 1$