Question

como resolvo essa equacao y²+5y-24=0

Answer 1

y^2+5y-24=0
delta=b^2-4.a.c
delta=5^2-4.1.(-24)
delta=25+96
delta=121
x=-b-/+ raiz de delta/2a
x=-5-11/2.1
x=-16/2
x=-8
x=-5+11/2.1
x=6/2
x=3