Question

Como resolvo :
4x2 - 4x + 1 = 4

Answer 1

4x² - 4x + 1 = 4

4x² - 4x + 1 - 4 = 0

4x² - 4x - 3 = 0

a = 4, b = - 4, c = - 3

$\Delta=b^2-4.a.c\\\Delta=(-4)^2-4.4.(-3)\\\Delta=16+48\\\Delta=64$

$x= \dfrac{-b \pm \sqrt{\Delta} }{2a} \\\\\\x= \dfrac{4 \pm 8}{8} \\\\\\x'= \dfrac{3}{2}\\\\\\x''= \dfrac{-1}{2}$


Forte abraço!