Question

como resolvo????

3y+2 = y²+3
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Answer 1

$\dfrac{3y+2}{2}=\dfrac{y^2+3}{3}\\\\\ 2(y^2+3)=3(3y+2)\\\\ 2y^2+6=9y+6\\\\ 2y^2-9y=0\\\\ y(2y-9)=0\Longrightarrow\begin{cases}y_1=0\\2y-9=0\rightarrow2y=9\rightarrow y_2=\frac{9}{2}\end{cases}\\\\S=\{0,\dfrac{9}{2}\}$