Question

como resolver? x²-16=0 e 6x²-7x+2=0

Answer 1

a) $x^{2} - 16 = 0 \\ \\ x^{2} = 16 \\ \\ x = \sqrt{16} \\ \\ x = 4 e x = -4$

b) $6 x^{2} -7x + 2 = 0$

Utilizando a fórmula resolvente (Baskara) temos:

Δ = 49-4.6.2 = 49-48 = 1 √Δ = √1 = 1

$x_{1} = \frac{7+1}{2.6} = \frac{8}{12} = \frac{2}{3} \\ \\ x_{2} = \frac{7-1}{2.6} = \frac{6}{12} = \frac{1}{2}$