Question

Como resolver??
(x+y)2-(x-y)2?
(3×+y)2?
(5+x)2?
(x-y)2-(x+y)2?
(x-2)×(x-5)?
(x+15)×(x-4)?
(x+3)2?​

Answer 1

Resposta:

(x+y)2-(x-y)2= 2x+2y-2x+2y= 4y

(3x+y)2= 6x+2y

(5+x)2= 10+x

(x-y)2-(x+y)2= 2x-2y-2x-2y=-2y

(x-2)×(x-5)=x×x-5x-2x+10=-7x+10+x ao quadrado

(x+15)×(x-4)=x×x-4x+15x-60= 11x-60+x ao quadrado

(x+3)2= 2x+6