Question

como resolver (x-4)ao quadrado=0

Answer 1

(x-4)²=0
(x-4)(x-4)=0
x²-4x-4x+16=0
x²-8x+16=0

aplica bhaskara
Delta=b²-4ac
Δ = b2 - 4.a.c 
Δ = -82 - 4 . 1 . 16 
Δ = 64 - 4. 1 . 16 
Δ = 0

x=-b+ -Raiz de delta/2a

-(-8)+- √0/2
8+0/2=4

x¹=4
x²=4